Optimal. Leaf size=438 \[ -\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\left (c d^2-a e^2\right ) \left (5 c^3 d^6-9 a c^2 d^4 e^2-a^2 c d^2 e^4-3 a^3 e^6\right ) x\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (15 c^3 d^6-31 a c^2 d^4 e^2+9 a^2 c d^2 e^4-9 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 c^2 d^2 e^3 \left (c d^2-a e^2\right )^3}-\frac {\left (5 c d^2+3 a e^2\right ) \tanh ^{-1}\left (\frac {c d^2+a e^2+2 c d e x}{2 \sqrt {c} \sqrt {d} \sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{2 c^{5/2} d^{5/2} e^{7/2}} \]
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Rubi [A]
time = 0.36, antiderivative size = 438, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 5, integrand size = 40, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {863, 832, 654,
635, 212} \begin {gather*} -\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (-3 a^2 e^4-10 a c d^2 e^2+5 c^2 d^4\right )+x \left (c d^2-a e^2\right ) \left (-3 a^3 e^6-a^2 c d^2 e^4-9 a c^2 d^4 e^2+5 c^3 d^6\right )\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {\left (-9 a^3 e^6+9 a^2 c d^2 e^4-31 a c^2 d^4 e^2+15 c^3 d^6\right ) \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{3 c^2 d^2 e^3 \left (c d^2-a e^2\right )^3}-\frac {\left (3 a e^2+5 c d^2\right ) \tanh ^{-1}\left (\frac {a e^2+c d^2+2 c d e x}{2 \sqrt {c} \sqrt {d} \sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}\right )}{2 c^{5/2} d^{5/2} e^{7/2}}-\frac {2 d x^3 \left (c d x \left (c d^2-a e^2\right )+a e \left (c d^2-a e^2\right )\right )}{3 e \left (c d^2-a e^2\right )^2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 635
Rule 654
Rule 832
Rule 863
Rubi steps
\begin {align*} \int \frac {x^4}{(d+e x) \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx &=\int \frac {x^4 (a e+c d x)}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx\\ &=-\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {2 \int \frac {x^2 \left (3 a c d^2 e \left (c d^2-a e^2\right )+\frac {1}{2} c d \left (5 c d^2-3 a e^2\right ) \left (c d^2-a e^2\right ) x\right )}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{3 c d e \left (c d^2-a e^2\right )^2}\\ &=-\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\left (c d^2-a e^2\right ) \left (5 c^3 d^6-9 a c^2 d^4 e^2-a^2 c d^2 e^4-3 a^3 e^6\right ) x\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {4 \int \frac {\frac {1}{2} a c d^2 e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\frac {1}{4} c d \left (c d^2-a e^2\right ) \left (15 c^3 d^6-31 a c^2 d^4 e^2+9 a^2 c d^2 e^4-9 a^3 e^6\right ) x}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{3 c^2 d^2 e^2 \left (c d^2-a e^2\right )^4}\\ &=-\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\left (c d^2-a e^2\right ) \left (5 c^3 d^6-9 a c^2 d^4 e^2-a^2 c d^2 e^4-3 a^3 e^6\right ) x\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (15 c^3 d^6-31 a c^2 d^4 e^2+9 a^2 c d^2 e^4-9 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 c^2 d^2 e^3 \left (c d^2-a e^2\right )^3}-\frac {\left (5 c d^2+3 a e^2\right ) \int \frac {1}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{2 c^2 d^2 e^3}\\ &=-\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\left (c d^2-a e^2\right ) \left (5 c^3 d^6-9 a c^2 d^4 e^2-a^2 c d^2 e^4-3 a^3 e^6\right ) x\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (15 c^3 d^6-31 a c^2 d^4 e^2+9 a^2 c d^2 e^4-9 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 c^2 d^2 e^3 \left (c d^2-a e^2\right )^3}-\frac {\left (5 c d^2+3 a e^2\right ) \text {Subst}\left (\int \frac {1}{4 c d e-x^2} \, dx,x,\frac {c d^2+a e^2+2 c d e x}{\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{c^2 d^2 e^3}\\ &=-\frac {2 d x^3 \left (a e \left (c d^2-a e^2\right )+c d \left (c d^2-a e^2\right ) x\right )}{3 e \left (c d^2-a e^2\right )^2 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {2 x \left (a d e \left (c d^2-a e^2\right ) \left (5 c^2 d^4-10 a c d^2 e^2-3 a^2 e^4\right )+\left (c d^2-a e^2\right ) \left (5 c^3 d^6-9 a c^2 d^4 e^2-a^2 c d^2 e^4-3 a^3 e^6\right ) x\right )}{3 c d e^2 \left (c d^2-a e^2\right )^4 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (15 c^3 d^6-31 a c^2 d^4 e^2+9 a^2 c d^2 e^4-9 a^3 e^6\right ) \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{3 c^2 d^2 e^3 \left (c d^2-a e^2\right )^3}-\frac {\left (5 c d^2+3 a e^2\right ) \tanh ^{-1}\left (\frac {c d^2+a e^2+2 c d e x}{2 \sqrt {c} \sqrt {d} \sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}\right )}{2 c^{5/2} d^{5/2} e^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.55, size = 300, normalized size = 0.68 \begin {gather*} \frac {\frac {\sqrt {c} \sqrt {d} \sqrt {e} (a e+c d x) \left (-9 a^4 e^7 (d+e x)^2+3 a^3 c d e^5 (3 d-e x) (d+e x)^2+c^4 d^7 x \left (15 d^2+20 d e x+3 e^2 x^2\right )+a c^3 d^5 e \left (15 d^3-11 d^2 e x-39 d e^2 x^2-9 e^3 x^3\right )+a^2 c^2 d^3 e^3 \left (-31 d^3-33 d^2 e x+9 d e^2 x^2+9 e^3 x^3\right )\right )}{\left (c d^2-a e^2\right )^3}-3 \left (5 c d^2+3 a e^2\right ) (a e+c d x)^{3/2} (d+e x)^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d} \sqrt {d+e x}}{\sqrt {e} \sqrt {a e+c d x}}\right )}{3 c^{5/2} d^{5/2} e^{7/2} ((a e+c d x) (d+e x))^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1111\) vs.
\(2(408)=816\).
time = 0.09, size = 1112, normalized size = 2.54
method | result | size |
default | \(\frac {\frac {x^{2}}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {3 \left (a \,e^{2}+c \,d^{2}\right ) \left (-\frac {x}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (-\frac {1}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (2 c d e x +a \,e^{2}+c \,d^{2}\right )}{c d e \left (4 a c \,d^{2} e^{2}-\left (a \,e^{2}+c \,d^{2}\right )^{2}\right ) \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}\right )}{2 c d e}+\frac {\ln \left (\frac {\frac {1}{2} a \,e^{2}+\frac {1}{2} c \,d^{2}+c d e x}{\sqrt {c d e}}+\sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}\right )}{c d e \sqrt {c d e}}\right )}{2 c d e}-\frac {2 a \left (-\frac {1}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (2 c d e x +a \,e^{2}+c \,d^{2}\right )}{c d e \left (4 a c \,d^{2} e^{2}-\left (a \,e^{2}+c \,d^{2}\right )^{2}\right ) \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}\right )}{c}}{e}-\frac {d \left (-\frac {x}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (-\frac {1}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (2 c d e x +a \,e^{2}+c \,d^{2}\right )}{c d e \left (4 a c \,d^{2} e^{2}-\left (a \,e^{2}+c \,d^{2}\right )^{2}\right ) \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}\right )}{2 c d e}+\frac {\ln \left (\frac {\frac {1}{2} a \,e^{2}+\frac {1}{2} c \,d^{2}+c d e x}{\sqrt {c d e}}+\sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}\right )}{c d e \sqrt {c d e}}\right )}{e^{2}}+\frac {d^{2} \left (-\frac {1}{c d e \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}-\frac {\left (a \,e^{2}+c \,d^{2}\right ) \left (2 c d e x +a \,e^{2}+c \,d^{2}\right )}{c d e \left (4 a c \,d^{2} e^{2}-\left (a \,e^{2}+c \,d^{2}\right )^{2}\right ) \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}\right )}{e^{3}}-\frac {2 d^{3} \left (2 c d e x +a \,e^{2}+c \,d^{2}\right )}{e^{4} \left (4 a c \,d^{2} e^{2}-\left (a \,e^{2}+c \,d^{2}\right )^{2}\right ) \sqrt {a d e +\left (a \,e^{2}+c \,d^{2}\right ) x +c d e \,x^{2}}}+\frac {d^{4} \left (-\frac {2}{3 \left (a \,e^{2}-c \,d^{2}\right ) \left (x +\frac {d}{e}\right ) \sqrt {c d e \left (x +\frac {d}{e}\right )^{2}+\left (a \,e^{2}-c \,d^{2}\right ) \left (x +\frac {d}{e}\right )}}+\frac {8 c d e \left (2 c d e \left (x +\frac {d}{e}\right )+a \,e^{2}-c \,d^{2}\right )}{3 \left (a \,e^{2}-c \,d^{2}\right )^{3} \sqrt {c d e \left (x +\frac {d}{e}\right )^{2}+\left (a \,e^{2}-c \,d^{2}\right ) \left (x +\frac {d}{e}\right )}}\right )}{e^{5}}\) | \(1112\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 901 vs.
\(2 (393) = 786\).
time = 7.73, size = 1817, normalized size = 4.15 \begin {gather*} \left [\frac {3 \, {\left (5 \, c^{5} d^{11} x + 6 \, a^{3} c^{2} d^{6} e^{5} - 3 \, a^{5} x^{2} e^{11} - 3 \, {\left (a^{4} c d x^{3} + 2 \, a^{5} d x\right )} e^{10} - {\left (2 \, a^{4} c d^{2} x^{2} + 3 \, a^{5} d^{2}\right )} e^{9} + {\left (4 \, a^{3} c^{2} d^{3} x^{3} + 5 \, a^{4} c d^{3} x\right )} e^{8} + 2 \, {\left (7 \, a^{3} c^{2} d^{4} x^{2} + 2 \, a^{4} c d^{4}\right )} e^{7} + 2 \, {\left (3 \, a^{2} c^{3} d^{5} x^{3} + 8 \, a^{3} c^{2} d^{5} x\right )} e^{6} - 6 \, {\left (2 \, a c^{4} d^{7} x^{3} + 3 \, a^{2} c^{3} d^{7} x\right )} e^{4} - {\left (19 \, a c^{4} d^{8} x^{2} + 12 \, a^{2} c^{3} d^{8}\right )} e^{3} + {\left (5 \, c^{5} d^{9} x^{3} - 2 \, a c^{4} d^{9} x\right )} e^{2} + 5 \, {\left (2 \, c^{5} d^{10} x^{2} + a c^{4} d^{10}\right )} e\right )} \sqrt {c d} e^{\frac {1}{2}} \log \left (8 \, c^{2} d^{3} x e + c^{2} d^{4} + 8 \, a c d x e^{3} + a^{2} e^{4} - 4 \, \sqrt {c d^{2} x + a x e^{2} + {\left (c d x^{2} + a d\right )} e} {\left (2 \, c d x e + c d^{2} + a e^{2}\right )} \sqrt {c d} e^{\frac {1}{2}} + 2 \, {\left (4 \, c^{2} d^{2} x^{2} + 3 \, a c d^{2}\right )} e^{2}\right ) + 4 \, {\left (15 \, c^{5} d^{10} x e - 9 \, a^{4} c d x^{2} e^{10} - 3 \, {\left (a^{3} c^{2} d^{2} x^{3} + 6 \, a^{4} c d^{2} x\right )} e^{9} + 3 \, {\left (a^{3} c^{2} d^{3} x^{2} - 3 \, a^{4} c d^{3}\right )} e^{8} + 3 \, {\left (3 \, a^{2} c^{3} d^{4} x^{3} + 5 \, a^{3} c^{2} d^{4} x\right )} e^{7} + 9 \, {\left (a^{2} c^{3} d^{5} x^{2} + a^{3} c^{2} d^{5}\right )} e^{6} - 3 \, {\left (3 \, a c^{4} d^{6} x^{3} + 11 \, a^{2} c^{3} d^{6} x\right )} e^{5} - {\left (39 \, a c^{4} d^{7} x^{2} + 31 \, a^{2} c^{3} d^{7}\right )} e^{4} + {\left (3 \, c^{5} d^{8} x^{3} - 11 \, a c^{4} d^{8} x\right )} e^{3} + 5 \, {\left (4 \, c^{5} d^{9} x^{2} + 3 \, a c^{4} d^{9}\right )} e^{2}\right )} \sqrt {c d^{2} x + a x e^{2} + {\left (c d x^{2} + a d\right )} e}}{12 \, {\left (c^{7} d^{12} x e^{4} - a^{4} c^{3} d^{3} x^{2} e^{13} - {\left (a^{3} c^{4} d^{4} x^{3} + 2 \, a^{4} c^{3} d^{4} x\right )} e^{12} + {\left (a^{3} c^{4} d^{5} x^{2} - a^{4} c^{3} d^{5}\right )} e^{11} + {\left (3 \, a^{2} c^{5} d^{6} x^{3} + 5 \, a^{3} c^{4} d^{6} x\right )} e^{10} + 3 \, {\left (a^{2} c^{5} d^{7} x^{2} + a^{3} c^{4} d^{7}\right )} e^{9} - 3 \, {\left (a c^{6} d^{8} x^{3} + a^{2} c^{5} d^{8} x\right )} e^{8} - {\left (5 \, a c^{6} d^{9} x^{2} + 3 \, a^{2} c^{5} d^{9}\right )} e^{7} + {\left (c^{7} d^{10} x^{3} - a c^{6} d^{10} x\right )} e^{6} + {\left (2 \, c^{7} d^{11} x^{2} + a c^{6} d^{11}\right )} e^{5}\right )}}, \frac {3 \, {\left (5 \, c^{5} d^{11} x + 6 \, a^{3} c^{2} d^{6} e^{5} - 3 \, a^{5} x^{2} e^{11} - 3 \, {\left (a^{4} c d x^{3} + 2 \, a^{5} d x\right )} e^{10} - {\left (2 \, a^{4} c d^{2} x^{2} + 3 \, a^{5} d^{2}\right )} e^{9} + {\left (4 \, a^{3} c^{2} d^{3} x^{3} + 5 \, a^{4} c d^{3} x\right )} e^{8} + 2 \, {\left (7 \, a^{3} c^{2} d^{4} x^{2} + 2 \, a^{4} c d^{4}\right )} e^{7} + 2 \, {\left (3 \, a^{2} c^{3} d^{5} x^{3} + 8 \, a^{3} c^{2} d^{5} x\right )} e^{6} - 6 \, {\left (2 \, a c^{4} d^{7} x^{3} + 3 \, a^{2} c^{3} d^{7} x\right )} e^{4} - {\left (19 \, a c^{4} d^{8} x^{2} + 12 \, a^{2} c^{3} d^{8}\right )} e^{3} + {\left (5 \, c^{5} d^{9} x^{3} - 2 \, a c^{4} d^{9} x\right )} e^{2} + 5 \, {\left (2 \, c^{5} d^{10} x^{2} + a c^{4} d^{10}\right )} e\right )} \sqrt {-c d e} \arctan \left (\frac {\sqrt {c d^{2} x + a x e^{2} + {\left (c d x^{2} + a d\right )} e} {\left (2 \, c d x e + c d^{2} + a e^{2}\right )} \sqrt {-c d e}}{2 \, {\left (c^{2} d^{3} x e + a c d x e^{3} + {\left (c^{2} d^{2} x^{2} + a c d^{2}\right )} e^{2}\right )}}\right ) + 2 \, {\left (15 \, c^{5} d^{10} x e - 9 \, a^{4} c d x^{2} e^{10} - 3 \, {\left (a^{3} c^{2} d^{2} x^{3} + 6 \, a^{4} c d^{2} x\right )} e^{9} + 3 \, {\left (a^{3} c^{2} d^{3} x^{2} - 3 \, a^{4} c d^{3}\right )} e^{8} + 3 \, {\left (3 \, a^{2} c^{3} d^{4} x^{3} + 5 \, a^{3} c^{2} d^{4} x\right )} e^{7} + 9 \, {\left (a^{2} c^{3} d^{5} x^{2} + a^{3} c^{2} d^{5}\right )} e^{6} - 3 \, {\left (3 \, a c^{4} d^{6} x^{3} + 11 \, a^{2} c^{3} d^{6} x\right )} e^{5} - {\left (39 \, a c^{4} d^{7} x^{2} + 31 \, a^{2} c^{3} d^{7}\right )} e^{4} + {\left (3 \, c^{5} d^{8} x^{3} - 11 \, a c^{4} d^{8} x\right )} e^{3} + 5 \, {\left (4 \, c^{5} d^{9} x^{2} + 3 \, a c^{4} d^{9}\right )} e^{2}\right )} \sqrt {c d^{2} x + a x e^{2} + {\left (c d x^{2} + a d\right )} e}}{6 \, {\left (c^{7} d^{12} x e^{4} - a^{4} c^{3} d^{3} x^{2} e^{13} - {\left (a^{3} c^{4} d^{4} x^{3} + 2 \, a^{4} c^{3} d^{4} x\right )} e^{12} + {\left (a^{3} c^{4} d^{5} x^{2} - a^{4} c^{3} d^{5}\right )} e^{11} + {\left (3 \, a^{2} c^{5} d^{6} x^{3} + 5 \, a^{3} c^{4} d^{6} x\right )} e^{10} + 3 \, {\left (a^{2} c^{5} d^{7} x^{2} + a^{3} c^{4} d^{7}\right )} e^{9} - 3 \, {\left (a c^{6} d^{8} x^{3} + a^{2} c^{5} d^{8} x\right )} e^{8} - {\left (5 \, a c^{6} d^{9} x^{2} + 3 \, a^{2} c^{5} d^{9}\right )} e^{7} + {\left (c^{7} d^{10} x^{3} - a c^{6} d^{10} x\right )} e^{6} + {\left (2 \, c^{7} d^{11} x^{2} + a c^{6} d^{11}\right )} e^{5}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{4}}{\left (\left (d + e x\right ) \left (a e + c d x\right )\right )^{\frac {3}{2}} \left (d + e x\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^4}{\left (d+e\,x\right )\,{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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